I am trying to do a list comprehension of a tuples list based on another list of tuples with partial match.
x = [((1,1),(1,1),(1,2)),
((2,1),(1,3),(2,9)),
((2,1),(2,3),(2,9))]
y = [(2,1),(1,3)]
[i for i in x for k in y if k in i]
e.g. in this x is a list of tuples & y is the desired list of tuples. If y is found in any of the items in the list of tuples in x, it should return that item.
Result is: [((2, 1), (1, 3), (2, 9)), ((2, 1), (1, 3), (2, 9)), ((2, 1), (2, 3), (2, 9))]
But I want only : [((2, 1), (1, 3), (2, 9))]
I tried with single tuple & it gave the desired result. But not sure why it doesn't work when I pass a tuple list.
x = [((1,1),(1,1),(1,2)),
((2,1),(1,3),(2,9)),
((2,1),(2,3),(2,9))]
y = (2,1)
[i for i in x if y in i]
Result: [((2, 1), (1, 3), (2, 9)), ((2, 1), (2, 3), (2, 9))]
You can use:
x = [
((1, 1), (1, 1), (1, 2)),
((2, 1), (1, 3), (2, 9)),
((2, 1), (2, 3), (2, 9)),
]
y = [(2, 1), (1, 3)]
print([t for t in x if not set(y).difference(t)])
output:
[((2, 1), (1, 3), (2, 9))]
If you subtract tuples inside x from y with set operations, if all the sub tuples are present, you'll end up with an empty set, so you want that tuple.
You could also write if set(y).issubset(t) instead of if not set(y).difference(t) part.(borrowed from @kellyBundy's answer)
What if I want any tpl of y to be true but not all.
print([t for t in x if set(y).intersection(t)])