PHP: Undefine variable when calling an object with in a function?

Question

I get "Undefine variable" from the following code.

This is all the code from index.php

<?php
include "globals.classes.php";
$anObj = new Globals();
logout();

function logout() {
    echo $anObj->getName(); //Warning: Undefined variable $anObj
    exit();
}
?>

I know passing $anObj in the parameter will work,

but is it possible to make it work without passing it through parameter?

I want to call a function this way..

logout();

not this...

logout($anObj);

Answer 1

That's because $anObj is out of scope. You need to either make logout() a member of Globals() and invoque it as:

<?php
include "globals.classes.php";
$anObj = new Globals();
$anObj->logout();

// In your class Global() you'll do something like this
class Globals {
   function getName() {}

   function logout() {
    echo $this->getName();
    exit();
   }
}
?>

Another solution could be this:

<?php
include "globals.classes.php";
$anObj = new Globals();
echo $anObj->getName();
logout()

function logout() {
    exit();
}

In that case you won't need logout(). But I guess you might want to do a few more things than just an exit()