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shellunixsh

Get domain home / base address from url with IP and Port in shell script

Have inputs like

url1='http://10.25.225.123:32782/actuator/health' url2='http://10.25.225.321:12345/myappmanagement/health' and so on.

How to get only http://10.25.225.123:32782/ and http://10.25.225.321:12345 for url1 and url2 respectively using the same command?

Solution 
  • url='http://10.25.225.123:32782/actuator/health'
awk -F'/' 'BEGIN{OFS=FS="/"} {print $1,$2,$3}' <<< "$url"
http://10.25.225.123:32782

    or simply:

    cut -d/ -f-3 <<< "$url"
http://10.25.225.123:32782