How to remove all file extensions in bash?

Question

x=./gandalf.tar.gz
noext=${x%.*}
echo $noext

This prints ./gandalf.tar, but I need just ./gandalf. I might have even files like ./gandalf.tar.a.b.c which have many more extensions.

I just need the part before the first .

Answer 1

If you want to give sed a chance then:

x='./gandalf.tar.a.b.c'
sed -E 's~(.)\..*~\1~g' <<< "$x"

./gandalf

Or 2 step process in bash:

x="${s#./}"
echo "./${x%%.*}"

./gandalf