select count(DISTINCT(a.cust_id)) as count ,b.code, b.name from table1 as a inner join table2 as b on a.par_id = b.id where a.data = "present" group by a.par_id order by b.name asc;
How to write this in sqlalchemy to get as expected results
The above query which is writen in sql should be right in sqlalchemy.
Thanks for inputs
Hope this works...
session.query(
func.count(distinct(table1.cust_id)).label('count'),
table2.code,
table2.name
).join(
table2,
table1.par_id == table2.id
).filter(
table1.data == "present"
).group_by(
table1.par_id
).order_by(
table2.name.asc()
).all()