How to count sum of prime numbers without a number 3?

Question

I have to count the sum of all prime numbers that are less than 1000 and do not contain the digit 3.

My code:

def primes_sum(lower, upper):
    total = 0
    for num in range(lower, upper + 1):
        if not num % 3 and num % 10:
            continue
        elif num > 1:
            for i in range(2, num):
                if num % i == 0:
                    break
            else:
                total += num
    return total

total_value = primes_sum(0, 1000)
print(total_value)

But still I don't have right result

Answer 1

def primes_sum(lower, upper):
    """Assume upper>=lower>2"""
    primes = [2]
    answer = 2
    for num in range(lower, upper+1):
        if any(num%p==0 for p in primes): continue  # not a prime

        primes.append(num)

        if '3' in str(num): continue
        answer += num

    return answer

The issue in your code was that you were checking for num%3, which checks whether num is divisible by 3, not whether it contains a 3.