remove entry in counter object if value meets condition

Question

Is there a way to remove entries from a counter object if the value matches a certain condition. For example:

Counter({'a': 1142,'b':1004,'c':100,'d':5})

I want to drop all indexes where it is less than 1000, so I just have 'a' and 'b' left. I know I can loop through each and then delete if it doesnt match the condition as shown in this solution. Just looking for a more efficient way.

Answer 1

I think it can be useful for you:

from collections import Counter
counter = Counter({'a': 1142, 'b': 1004, 'c': 100, 'd':5})
Counter({k: c for k, c in counter.items() if c >= 1000})

Output:

Counter({'a':1142 , 'b': 1004})

This way is more effective as you mentioned.