random float numbers and their mean and standart deviation

Question

how to get a list of 1000 random float numbers without dublicates and find their mean value in python?

import random
rnd_number=random.random()
def a():
        l=[]
        m=1
        for i in range(1000):
                l.append(rnd_number)
        return l
        for i in l:
                m=m+i
        return m//b
print (a())

i am probably wrong with returning l before the other operation but when the code works there are 1000 of the same float numbers on the screen

Answer 1

Hope this would help!

import numpy as np
import random

N=10
# number of digits you want after the .dot sign
# more digits .dot ensure mo duplication
Npts=1000
# number of random numbers
num=[]
# initialize the array
for m in range(1000):
    nm=round(random.random(), N)
    # local variable to take the random numbers
    num.append(nm)
    # append the random number nm to the original num array
print(num)
# printing the random numbers

# Let's check is there is a duplication or not
my_num=set(num)
if len(num)!=len(my_num):
    print("Duplication in the array")
else:
    print("NO duplication in the array")

# Calculating mean
avg=sum(num)/Npts
print(avg)