I have the dataframes df, df1, and the list l1 as follows :
df = data.frame(x = c(1,0,0,0,1,1,1,NA), y = c(2,2,2,2,3,3,2,NA),
z = c(1:7,NA), m = c(1,2,3,1,2,3,1,NA) )
df$x = factor(df$x)
df$y = factor(df$y)
df$m = factor(df$m)
df1 = df%>%select_if(is.factor)
l1 = lapply(df1,table(useNA = 'always'))
when trying to include the useNA
argument in l1 list, it doesn't work. However, when applying the argument for each variable like for example table(df1$x,useNA = 'always')
, it works properly. Would appreciate the help to handle this error.
The proper format for lapply is "lapply(X, FUN, ...)" where the ... are for the optional arguments for the function.
So in this case the argument: useNA = 'always'
becomes:
lapply(df1, table, useNA = 'always')