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rsubstringnumericsubstr

Getting last two digits of Sequence Date in R

I have sequence date:

names<-format(seq.Date(as.Date("2012-11-01"),as.Date("2012-12-01"),
                by = 'months'),format = "%Y%m")

How can I get the last two digit, like the result for last two digits of names[1] is 11?

Solution

  • Using the stringr package you can just put

    stringr::str_sub(string = names, start = -2, end = -1)