Background
- I am on macOS 12.6.1
- I installed pyenv via homebrew
- I installed 3.10.7 via pyenv
pyenv install 3.10.7
- I set 3.10.7 to global with
pyenv global 3.10.7
- I have installed ipykernel with `pip install ipykernel'
- My .zshrc file contains the following:
export PYENV_ROOT="$HOME/.pyenv"
command -v pyenv >/dev/null || export PATH="$PYENV_ROOT/bin:$PATH"
eval "$(pyenv init -)"
Under 'Python: Select interpreter' I have four options:
- Enter interpreter path...
- Use Python from 'python.defaultInterpreterPath' setting ~/.pyenv/versions/3.10.7/bin/python
- Python 3.10.7 64-bit('3.10.7':penv) ~/.pyenv/versions/3.10.7/bin/python Recommended
- Python 3.9.6 64-bit /usr/bin/python3 Global
If I type `python --version' in the terminal, I get Python 3.10.7
If I click on the kernel selection button (top right), I have the following option:
- Python 3.9.6 64-bit /usr/bin/python3 Currently selected Suggested
- Connect to a Jupyter Server
Could someone clarify/help me understand the interpreter vs kernel settings in Visual Studio Code?
How can I add the option of using Python 3.10.7 to the kernel?
I've managed to get Python 3.10.7 to become available in the kernel option. What I did was:
- File -> Open folder -> Desktop
- Made a new python file, test.py, which contained some python code:
a = 4
b = 2
c = a + b
print(c)
- Ran the python file, made sure that output (c) was printed.
- Then cmd + shift + p + navigate to 'Jupyter filter kernels'
- Selected 3.10.7 and unselected Python 3.9.6
- Made a new jupyter notebook file, and the kernel option was already preselected as 3.10.7.
I don't know which part of my actions actually were required for it to get working, I'm sure that someone of them were not relevant, but it's working now.