I want to check if a log file has any instance where two or more consecutive lines contains the same text using bash. The text will be specified. The timestamp and any other text after the third field are to be ignored in the comparison.
i.e grep... "error" /tmp/file.txt
this file will match:
2020-01-01 05:05 text1
2020-01-01 05:07 error
2020-01-01 05:15 error
2020-01-01 05:25 error
2020-01-01 05:45 text2
this won't
2020-01-01 05:05 text1
2020-01-01 05:15 error
2020-01-01 05:25 text2
2020-01-01 05:45 error
2020-01-01 05:05 text3
Any ideas using grep, sed or awk? Ideally I'd like to have an exit value 0 for match and 1 for not match.
Looks like uniq does everything you need.
-d, --repeated
only print duplicate lines, one for each group
-s, --skip-chars=N
avoid comparing the first N characters
So this should work for you:
uniq --skip-chars=17 -d /tmp/file.txt
Tested on my machine:
$ cat in.txt
2020-01-01 05:05 text1
2020-01-01 05:07 error
2020-01-01 05:15 error
2020-01-01 05:25 error
2020-01-01 05:45 text2
$ uniq --skip-chars=17 -d in.txt
2020-01-01 05:07 error