Retrieve records with unique or largest string in that column which contains other strings in that column and matching count

Question

I have the following table:

this_table (phrase is always unique)

phrase	count
elemo	11
e	37
elemo a	11
r sundt	6
wit	102
lolo m	102
o	1475
mo	111
lo m	186
domo	111

I'd like a query that removes results if their (record A) phrase is contained within another record's (record B) phrase AND their (record A) count matches the containing record's (record B) count.

Results

phrase	count
e	37
elemo a	11
r sundt	6
wit	102
lolo m	102
o	1475
lo m	186
domo	111

Answer 1

You didn't specify the database, but this should do it. The idea is about the same as suggested by Barmar in the comments. I find it easier to implement the logic using not exists

with cte (phrase, counts) as
  
(select 'elemo',    11  union all
 select 'e',        37  union all
 select 'elemo a',  11  union all
 select 'r sundt',  6   union all
 select 'wit',     102  union all
 select 'lolo m',  102  union all
 select 'o',       1475 union all
 select 'mo',      111  union all
 select 'lo m',    186  union all
 select 'domo',    111)

select *
from cte a
where not exists (select *
                  from cte b
                  where a.counts=b.counts and 
                        a.phrase <> b.phrase and 
                        a.phrase like concat('%',b.phrase,'%'))