I need your help trying to understand how I could combine some actions to get to the expected results. So i have the following path, in which I have many files:
/home/application/Upload_Actions/TestFiles/
Now, the files have the following name:
DATE20220703.2130_Network=MainPipeline,Action=Upload_File,Element=X988Schema_1000_statsfile.csv
What I want is to iterate over all the files from within that folder, and replace the _ from its name with :.
The file should look like:
DATE20220703.2130_Network=MainPipeline,Action=Upload_File,Element=X988Schema:1000_statsfile.csv
I have written a small one line for, but I am not quite sure how to iterate to the NTH occurence of the symbol _.
for f in ./*statsfile*; do mv "$f" "${f//_/:}"; done
The thing is that it does the following thing: From:
/home/application/Upload_Actions/TestFiles/DATE20220703.2130_Network=MainPipeline,Action=Upload_File,Element=X988Schema_1000_statsfile.csv
To: (but it failes doe to NO SUCH FILE or DIRECTORY because it replaces the _ from the path)
/home/application/Upload:Actions/TestFiles/DATE20220703.2130_Network=MainPipeline,Action=Upload:File,Element=X988Schema:1000:statsfile.csv
How could I do that only the 3rd occurence of the _ symbol gets replaced, so that the _ symbol from the path and the first _ symbol from from the title are left alone? Expected results:
/home/application/Upload_Actions/TestFiles/DATE20220703.2130_Network=MainPipeline,Action=Upload_File,Element=X988Schema:1000_statsfile.csv
OS Version: CENTOS 7
How about replacing the second occurence from the end? Like:
for file in ./*statsfile*; do
head=${file%_*_*}
tail=${file#"$head"_}
echo mv "$file" "$head:$tail"
done
Remove echo to actually move the files.