Can anyone help, im new to coding, im trying to create a document generator program that replaces placeholder words(words in curly braces,eg :{{NAME}}) in existing word documents(via path) by using tkinter entry widgets which then generates a new word document with the new changes,but i cant get the entry widget to work with the the dictionary(it uses the dictionary to swap the keys for the values using docxtemplate).simply put i want the value in the dictionary to be dynamic and changes based on a user's entry input so it can be swapped with its key,if that makes sense.i was inspired by this video on youtube https://youtu.be/fziZXbeaegc.here is a basic code(Note:i dont get any errors):
from pathlib import Path
from docxtpl import DocxTemplate
from tkinter import *
document_path = Path(__file__).parent / (r"C:\Users\Acer\Desktop\python\My name is.docx")
doc = DocxTemplate(document_path)
#define submit
def submit():
doc.render(swap)
doc.save(Path(__file__).parent / "generated_doc.docx")
#The app window
root = Tk()
#input field properties
entry=Entry(root,
font=("Arial",15))
entry.pack(side=LEFT)
swap={"NAME" : "Joe"}
#document generation button propeties
generate_button=Button(root,text="Generate",command=submit)
generate_button.pack(side=RIGHT)
root.mainloop()
Two things.
First, this is probably a bug, since the second part is already a full path.
document_path = Path(__file__).parent / (r"C:\Users\Acer\Desktop\python\My name is.docx")
That should be:
document_path = Path(r"C:\Users\Acer\Desktop\python\My name is.docx")
Second, you need to modify the dictionary with the contents of the Entry before the conversion.
def submit():
# The following line updates the dictionary.
swap["NAME"] = entry.get()
doc.render(swap)
doc.save(Path(__file__).parent / "generated_doc.docx")
And a suggestion. Instead of hardcoding a filename, use filedialog.askopenfilename() from a button callback to get the name of the file to process, like this:
fn = filedialog.askopenfilename(
title='Word file to open',
parent=root,
defaultextension='.docx',
filetypes=(('Word files', '*.doc*'), ('all files', '*.*')),
)
After this returns, fn contains the path of the selected file.