Ruby case statement on a hash?

Question

This is going to sound weird, but I would love to do something like this:

case cool_hash
  when cool_hash[:target] == "bullseye" then do_something_awesome
  when cool_hash[:target] == "2 pointer" then do_something_less_awesome
  when cool_hash[:crazy_option] == true then unleash_the_crazy_stuff
  else raise "Hell"
end

Ideally, I wouldn't even need to reference the has again since it's what the case statement is about. If I only wanted to use one option then I would "case cool_hash[:that_option]", but I'd like to use any number of options. Also, I know case statements in Ruby only evaluate the first true conditional block, is there a way to override this to evaluate every block that's true unless there is a break?

Answer 1

in ruby 3.0 you can do the following with pattern matching

# assuming you have these methods, ruby 3 syntax
def do_something_awesome = "something awesome 😎"
def do_something_less_awesome = "something LESS awesome"
def unleash_the_crazy_stuff = "UNLEASH the crazy stuff 🤪"

you can do

def do_the_thing(cool_hash)
  case cool_hash
  in target: "bullseye" then do_something_awesome
  in target: "2 pointer" then do_something_less_awesome
  in crazy_option: true then unleash_the_crazy_stuff
  else raise "Hell"
  end
end

will return

do_the_thing(target: "bullseye")
=> "something awesome 😎"

do_the_thing(target: "2 pointer")
=> "something LESS awesome"

do_the_thing(crazy_option: true)
=> "UNLEASH the crazy stuff 🤪"

in ruby 2.7 it still works

# need to define the methods differently
def do_something_awesome; "something awesome 😎"; end
def do_something_less_awesome; "something LESS awesome"; end
def unleash_the_crazy_stuff; "UNLEASH the crazy stuff 🤪"; end

# and when calling the code above to do the switch statement
# you will get the following warning
warning: Pattern matching is experimental, and the behavior may change
         in future versions of Ruby!