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xsl-fo

how to wrap the long word (containing more than hundred characters) in XSL FO

sorry for disturbance. I want to print a word "c_sunil_folder1_folder2_folder3_folder4_folder5_folder6_suniltext.pdf" in a table cell using XSL FO but the length of word is so long and also can contains more than hundred characters in a word so it is not wrapping in a single column

Could any one suggest a solution if it is possible to wrap with in a column

<fo:table-cell xsl:use-attribute-sets="table.cell" border-top="none" keep-together.within-line="always">
<fo:block keep-together.within-line="always">
<fo:inline><xsl:value-of select="'c_sunil_folder1_folder2_folder3_folder4_folder5_folder6_suniltext.pdf'"/>
</fo:inline>
</fo:block>
.
.
.

Output: In the output we can see that text is overlapping in next column of table:

Text is overlapping in next column text

Solution

  • The first thing to do is remove the keep-together.within-line="always" that is keeping everything to one line.

    The watermark on your screenshot suggests that you could be using Antenna House Formatter. If so, you can use axf:word-break="break-all" (see https://www.antenna.co.jp/AHF/help/en/ahf-ext.html#axf.word-break) to allow Antenna House Formatter to break anywhere within a word.

    Otherwise, the usual technique is to use XSLT to insert a ZERO-WIDTH SPACE between every character in a table cell. See How to force wrap on table entries