In R, when I use the following code to generate a table with the data.frame() command:
nn <- 10
df <- data.frame(Completers = rep(c(1, 0), each = nn),
Gender = c(1, 0))
I get this result:
Completers Gender
1 1 1
2 1 0
3 1 1
4 1 0
5 1 1
6 0 0
7 0 1
8 0 0
9 0 1
10 0 0
However, when I try to do the same with tibble::tibble():
tb <- tibble::tibble(Completers = rep(c(1, 0), each = nn),
Gender = c(1, 0))
I get the following error:
Error:
! Tibble columns must have compatible sizes.
• Size 10: Existing data.
• Size 2: Column `Gender`.
ℹ Only values of size one are recycled.
Run `rlang::last_error()` to see where the error occurred.
Needless to say that running rlang::last_error() does not help (me, at least).
Of course, I could simply tb <- tibble::as_tibble(df) and get on with my life, but still...
Therefore, my question is:
tibble() code equivalent of data.frame() in order to have the same result as above?sessioninfo::session_info() extract:
setting value
version R version 4.2.1 (2022-06-23)
os macOS Monterey 12.6
system x86_64, darwin17.0
rstudio 2022.07.1+554 Spotted Wakerobin (desktop)
-------------------------------------------------------
package * version date (UTC) lib source
tibble 3.1.8 2022-07-22 [1] CRAN (R 4.2.0)
It is mentioned in the ?tibble documentation
tibble() builds columns sequentially. When defining a column, you can refer to columns created earlier in the call. Only columns of length one are recycled.
> tibble::tibble(Completers = rep(c(1, 0), each = nn), Gender = 1)
# A tibble: 20 × 2
Completers Gender
<dbl> <dbl>
1 1 1
2 1 1
3 1 1
4 1 1
5 1 1
6 1 1
7 1 1
8 1 1
9 1 1
10 1 1
11 0 1
12 0 1
13 0 1
14 0 1
15 0 1
16 0 1
17 0 1
18 0 1
19 0 1
20 0 1
If we want to get the same output, use rep with length.output
tibble::tibble(Completers = rep(c(1, 0), each = nn),
Gender = rep(c(1, 0), length.out = length(Completers)))
# A tibble: 20 × 2
Completers Gender
<dbl> <dbl>
1 1 1
2 1 0
3 1 1
4 1 0
5 1 1
6 1 0
7 1 1
8 1 0
9 1 1
10 1 0
11 0 1
12 0 0
13 0 1
14 0 0
15 0 1
16 0 0
17 0 1
18 0 0
19 0 1
20 0 0