In this very simple example, is it possible in CSS to:
I can make a second more narrow div to hold the black lines as a repeating linear gradient and position it in the center of the gray div; but wondered if it is possible with one div.
I see that they can make complex plaid designs with gradients and all kinds of intricate things; but I'm not at all all artistic and a few perpendicular lines is a challenge.
Thanks for any direction you may be able to provide.
:root { --start: 8.0rem; }
html { font-size: 62.5% }
div {
width: 50px;
height: 20.0rem;
background-color: rgb(200,200,200);
background-image: linear-gradient( to bottom,
transparent var(--start),
black var(--start), black calc(var(--start) + 0.1rem),
transparent calc(var(--start) + 0.1rem), transparent calc(var(--start) + 0.3rem),
black calc(var(--start) + 0.3rem), black calc(var(--start) + 0.4rem),
transparent calc(var(--start) + 0.4rem), transparent calc(var(--start) + 0.6rem),
black calc(var(--start) + 0.6rem), black calc(var(--start) + 0.7rem),
transparent calc(var(--start) + 0.7rem), transparent calc(var(--start) + 0.9rem),
black calc(var(--start) + 0.9rem), black calc(var(--start) + 1.0rem),
transparent calc(var(--start) + 1.0rem), transparent calc(var(--start) + 1.2rem),
black calc(var(--start) + 1.2rem), black calc(var(--start) + 1.3rem),
transparent calc(var(--start) + 1.3rem), transparent calc(var(--start) + 1.5rem),
black calc(var(--start) + 1.5rem), black calc(var(--start) + 1.6rem),
transparent calc(var(--start) + 1.6rem), transparent
);
}
<div></div>
You can define a size and position for a gradient
:root { --start: 8.0rem; }
html { font-size: 62.5% }
div {
width: 50px;
height: 20.0rem;
background:
repeating-linear-gradient(black 0 0.1rem,#0000 0 0.3rem)
center/ /* position */
60% 1.6rem /* size (width height) */
no-repeat /* don't repeat */
rgb(200,200,200); /* background color */
}
<div></div>
Related:
Error: CSS: background: / is an incorrect operator
Issues with "background-position" in "background" shorthand property