write a variable that takes a list of functions

Question

I want to write a variable that takes a list of functions, is that even possible? to have a list of functions in C?

example:

// this type is for one function
void (*f)(void) = func1;

// but this is what I need
/*TYPE*/ vf = { func1, func2, NULL };

I dont want to build new struct that hold the function and the next function, I want to like i mentioned above, is that possible without creating a dedicated struct?

note: I am not bound to a specific C standard

Answer 1

This record

void (*f)(void) = func1;

declares one pointer to function.

This record

void ( * vf[] )( void ) = { func1, func2, NULL };

or

void ( * vf[3] )( void ) = { func1, func2, NULL };

declares an array of pointers to functions.

You could simplify the declaration using a typedef either for the function type or for a pointer to the function type as for example

typedef void Func( void );
Func * vf[3] = { func1, func2, NULL };

or

typedef void ( *FuncPtr )( void );
FuncPtr vf[3] = { func1, func2, NULL };