C++: 2D Dyanamic Arrays, outputting all values in one line

Question

so I'm starting to write a program that multiplies two square matrices using dynamic 2D arrays. I'm just learning how dynamic arrays work, so I'm testing to make sure everything is storing properly.

When I run my code, it outputs the two matrices on a single line each, rather than like a matrix with rows and columns. How do I fix this?

#include <iomanip> 
#include <iostream>
#include <array>

using namespace std;

int main()
{
  int **C, n, m; //pointer, rows, columns for matrix 1;
  int **D, p, q; //pointer, rows, columns for matrix 2;
  cout << "Enter the dimensions of your matrices: ";
  cin >> n >> m;
  p = n;
  q = m;
  cout << endl;
  C = new int *[n];
  D = new int *[p];
  for (int x=0 ; x < n; x++)
    {
      C[x] = new int [m];
    }

  for (int x=0 ; x < p; x++)
    {
      D[x] = new int [q];
    }

  cout << "Enter the values of your first matrix: ";
  for (int I=0 ; I < n; I++ )
    {
    for (int K=0 ; K < m; K++) 
      cin >> C[I][K];
    }

  cout << "Enter the values of your second matrix: ";
  for (int L=0 ; L < p; L++ )
    {
    for (int Z=0 ; Z < q; Z++) 
      cin >> D[L][Z];
    }
    
  for (int I=0 ; I < n; I++ )
    {
      for (int K=0 ; K < m; K++)
        cout << setw(4)<< C[I][K];
    }

  cout <<  endl;

  for (int L=0 ; L < p; L++ )
    {
      for (int Z=0 ; Z < q; Z++)
        cout << setw(4)<< D[L][Z];
    }
  
  cout << endl;
  
  }

Answer 1

Just add one more statement

cout <<  endl;

in your for loops like

for (int I=0 ; I < n; I++ )
{
  for (int K=0 ; K < m; K++)
    cout << setw(4)<< C[I][K];
  cout <<  endl;
}

cout <<  endl;

for (int L=0 ; L < p; L++ )
{
  for (int Z=0 ; Z < q; Z++)
    cout << setw(4)<< D[L][Z];
  cout <<  endl;
}

cout << endl;