How to replace string after colon using sed, awk, regex, yq etc and can run using shell script

Question

I have a yaml file and in that file I need to replace a specific string that comes after oauth2accesstoken: using a shell script

my current shell script :-

#!/bin/sh

password=$(gcloud auth print-access-token)

password="$password" yq -i '.stringData.creds |= "oauth2accesstoken:" + strenv(password)' /test.yaml

Lets Assume Replace Value is "abcdefg1234"

File :-

kind: Secret
metadata:
  name: cred
type: Opaque
stringData:
  creds: oauth2accesstoken:ya29.a0AJ8fv7hrWsNVlDaXa-j6IUwBRdxt6GDDXMu1234efrtyhAjPWx0uw0174 # dummy key

Output Should be like this:-

kind: Secret
metadata:
  name: cred
type: Opaque
stringData:
  creds: oauth2accesstoken:abcdefg1234

Error:-

Error: unknown command ".stringData.creds |= \"oauth2accesstoken:\" + strenv(password)" for "yq"
Run 'yq --help' for usage.

Note:-Above keys are dummy keys.

Answer 1

With Go yq aka mikefarah/yq, its pretty straightforward to just select the right field and update its value

yq '.stringData.creds |= "oauth2accesstoken:abcdefg1234"' yaml

or pass the value from a shell variable

token="abcdefg1234" yq '.stringData.creds |= "oauth2accesstoken:" + strenv(token)' yaml

To modify the file in-place use the -i flag e.g. yq -i <rest-of-the-code>. Tested on version 4.27.5