How would I get the height and width of a video from ffmpeg's information output. For example, with the following output:
$ ffmpeg -i video.mp4
...
Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'video.mp4':
Metadata:
major_brand : isom
minor_version : 1
compatible_brands: isomavc1
creation_time : 2010-01-24 00:55:16
Duration: 00:00:35.08, start: 0.000000, bitrate: 354 kb/s
Stream #0.0(und): Video: h264 (High), yuv420p, 640x360 [PAR 1:1 DAR 16:9], 597 kb/s, 25 fps, 25 tbr, 25k tbn, 50 tbc
Metadata:
creation_time : 2010-01-24 00:55:16
Stream #0.1(und): Audio: aac, 44100 Hz, stereo, s16, 109 kb/s
Metadata:
creation_time : 2010-01-24 00:55:17
At least one output file must be specified
How would I get height = 640, width= 360?
Have a look at mediainfo Handles most of the formats out there.
If you looking for a way to parse the output from ffmpeg, use the regexp \d+x\d+
Example using perl:
$ ./ffmpeg -i test020.3gp 2>&1 | perl -lane 'print $1 if /(\d+x\d+)/'
176x120
Example using python (not perfect):
$ ./ffmpeg -i /nfshome/enilfre/pub/test020.3gp 2>&1 | python -c "import sys,re;[sys.stdout.write(str(re.findall(r'(\d+x\d+)', line))) for line in sys.stdin]"
[][][][][][][][][][][][][][][][][][][]['176x120'][][][]
Python one-liners aren't as catchy as perl ones :-)