Error return a function using if-else shorthand in python

Question

I'm trying to use this if-else shorthand inside a function:

def isFull(): # checks wheteher stack is full
    return True if top == (size - 1) else return False

But my IDE highlights the return saying "Expected expression".

What is wrong with the code, and how do I fix it?

Answer 1

You don't repeat return inside the conditional expression. The conditional expression contains expressions, return is a statement.

def isFull():
    return True if top == (size - 1) else False

But there's really no reason for the conditional expression at all, just return the value of the condition, since it's True or False.

def isFull():
    return top == size - 1