Keras Sequential Compile Function TypeError : compile() missing 1 required positional argument: 'self'

Question

This is my Keras model

model = keras.Sequential
(
    [
        Dense(2, activation="relu", name="L1"),
        Dense(3, activation="relu", name="L2"),
        Dense(4,name="L3")
    ]
)

and in the next line i use compile() function on my model

model.compile(optimizer="sgd", loss="mse", metrics=[MeanSquaredError()])

but i get this TypeError when i run it

TypeError: compile() missing 1 required positional argument: 'self'

Answer 1

first of all you need to understand how many input and outputs you have. for example you want to detect the 5 class than your last layer should have 5 as dense attributes. so add this as model

model=tf.keras.models.Sequential([
    tf.keras.layers.Conv2D(16,(3,3),activation='relu',input_shape=(224,224,3)),
    tf.keras.layers.MaxPool2D(2,2),
    #1
    tf.keras.layers.Conv2D(32,(3,3),activation='relu'),
    tf.keras.layers.MaxPool2D(2,2),
    #2
    tf.keras.layers.Conv2D(64,(3,3),activation='relu'),
    tf.keras.layers.MaxPool2D(2,2),
    #
    #
    tf.keras.layers.Flatten(),
    #
    tf.keras.layers.Dense(512,activation='relu'),
    #
    tf.keras.layers.Dense(4,activation='softmax')

    ]
)

than compile your model

model.compile(optimizer=tf.keras.optimizers.RMSprop(learning_rate=0.01),
              loss='categorical_crossentropy',metrics=['accuracy'])

this will work.