Incorrect path to my file when I try to restart it

Question

I am trying to execute this:

os.execv(sys.executable, ['python'] + sys.argv)

The result I am getting:

C:\Program Files\Python310\python.exe: can't find '__main__' module in 'c:\\Users\\user\\OneDrive\\Рабочий'

As you can see, the path after the 'module in' words is improper. I printed sys.argv and got:

c:/Users/user/OneDrive/Рабочий стол/myfolder/file.py

Answer 1

This is how to os.execv into another program passed in the command line:

# as execv_argv.py
import os
import sys

os.execv(sys.executable, [sys.executable] + sys.argv[1:])

and call with

python execv_argv.py "second exec.py"

Note os.execv with full sys.argv will call the parent again forever.