I am trying to define a function that takes nested lists and outputs:
(1) How many lists are in the list,
and (2) Whether the number of elements in each list are the same.
I have two nested lists:
nl1: [[1, 2, 3, 4, 5], [3, 4, 5, 6, 7], [2, 4, 6, 8, 10]]
nl2: [[1, 2, 3, 4, 5], [3, 4, 6, 7], [2, 4, 6, 8, 10]]
the function name is nlc() nested list count
nl1 = [[1, 2, 3, 4, 5], [3, 4, 5, 6, 7], [2, 4, 6, 8, 10]]
nl2 = [[1, 2, 3, 4, 5], [3, 4, 6, 7], [2, 4, 6, 8, 10]]
def nlc(n):
sl = len(n)
print("Number of Lists is", sl)
for list in n:
r = list(map(len, n))
if r ==list()
print("Lengths Match")
else print("Lengths Not Equal; Check Lists")
Two things:
(P1) Python keeps returning an error saying that r = list(map(len, n)) is wrong because it is a string.
(P2) I can't seem to figure out how to write the code that checks whether each nested list has the same number of elements.
Moreover, when I test P1, it runs just fine:
nl1 = [[1, 2, 3, 4, 5], [3, 4, 5, 6, 7], [2, 4, 6, 8, 10]]
r = list(map(len, nl1))
print(r)
So I am not sure what's happening to the argument with I am defining the function.
I suppose you are using list() built-in method and also using it as a variable in a loop, this is causing an error. You can do the same task as this
#Function definition
def nlc(n):
'''It checks how many lists are in the list, and whether the number of elements in each list are the same.'''
sl = len(n)
print("Number of Lists is", sl)
lengths = []
for element in n:
lengths.append(len(element)) #appending length of each sublist
if len(set(lengths)) == 1: #checking if all elements are same in a list. It means that all lengths are equal
print("Lengths Match")
else:
print("Lengths Not Equal; Check Lists")
nl1 = [[1, 2, 3, 4, 5], [3, 4, 5, 6, 7], [2, 4, 6, 8, 10]]
nl2 = [[1, 2, 3, 4, 5], [3, 4, 6, 7], [2, 4, 6, 8, 10]]
nlc(nl2)