I am trying to solve a problem where recursion is a must. The tasks is: Write a function that takes in an integer n and returns the highest integer in the corresponding Collatz sequence.
My solution is this:
collatz = []
def max_collatz(num):
collatz.append(num)
if num == 1:
return max(collatz)
else:
return max_collatz(num / 2) if num%2 == 0 else max_collatz((3 * num) + 1)
However, I need to find a way to solve it without using a list outside of the function. I really couldn't find a solution, is there any?
It's either the current number or the largest in the rest of the sequence.
def max_collatz(n):
if n == 1:
return 1
elif n % 2:
return max_collatz(3 * n + 1)
else:
return max(n, max_collatz(n // 2))