Marking the last character from the matched string

Question

I want to mark the last character from the matched string in regex101 or notepad++ regex. To be marked the last space before the }.

Here’s my example(tried), Regex: https://regex101.com/r/0QNOD1/1

input:

[]*}+%>++~€_€<]%,!!_€~
“ABC/A1/YY-“+abc1 
    }
!£|€_€{^}?![+}|!¥]
“ABC/A2/YY-“+abc2
    }
18,&4&5&4&&1$&((&&1
“ABC/A3/YY-“+abc7
    }

Result After Replacement

[]*}+%>++~€_€<]%,!!_€~
“ABC/A1/YY-“+abc1 
    SEND}
!£|€_€{^}?![+}|!¥]
“ABC/A2/YY-“+abc2
    SEND}
18,&4&5&4&&1$&((&&1
“ABC/A3/YY-“+abc7
    SEND}

Answer 1

You can search using this regex:

ABC/A\d+/YY-“\+abc\d+\s*[\s\S]?+\K(?=})

And replace it with:

SEND

Updated RegEx Demo

RegEx Details:

• ABC/A: Match ABC/A
• \d+: Match 1+ digits
• /YY-“\+abc:
• \d+: Match 1+ digits
• \s*: Match 0+ whitespaces
• [\s\S]?+: Match an optional character including line break. + after ? is possessive quantifier.
• \K: Reset match info
• (?=}): Lookahead to make sure we have } at next position