Correct one-liner list comprehension

Question

I have the following list and string:

words = ['AIBONITO', 'BICINIUM', 'LIMONIUM', 'PICKNICK', 'SILENIUM', 'TITANIUM']
letters = 'ADEOLR'

I want to delete items in the list that contain a letter in the string. The following code does just that.

code:

for letter in letters:
    for word in words:
        if letter in word:
            words.remove(word)
print(words)

output:

['BICINIUM', 'PICKNICK']

Now I would like to convert it to a one-liner. I tried to do it by using the following code:

print([words for letter in letters for word in words if letter not in word])

This gives me a list with 12 items all containing ['BICINIUM', 'PICKNICK']. What do I need to change in the one-liner to obtain the same output as the first piece of code?

I know I can add "[0]" at the end of the one-liner but that's not really clean.

Answer 1

using all allows to do that.

words = ['AIBONITO', 'BICINIUM', 'LIMONIUM', 'PICKNICK', 'SILENIUM', 'TITANIUM']
letters = 'ADEOLR'

result = [word for word in words if all(letter not in word for letter in letters)]

yields:

['BICINIUM', 'PICKNICK']

An alternative uses a set of letters for the same result:

letters = set('ADEOLR')

result = [word for word in words if letters.isdisjoint(word)]