How to search end of the digit from this two srting which is 0.12%?
text1 = '20% of the modern marijuana terpene profile. Myrcene has a distinct earthy, musky flavor, resembling cloves. It is responsible for calming and soothing effects of weed. Myrcene is also found in hops, thyme, mango, lemongrass, guava melon. 0.12%'
text2 = 'The modern marijuana terpene profile. Myrcene has a distinct earthy, musky flavor, resembling cloves. It is responsible for calming and soothing effects of weed. Myrcene is also found in hops, thyme, mango, lemongrass, guava melon. 0.12%'
I tried this which worked for text2 but not getting expected result for text1 like text2
re.search(r'(\d.*)',text)
but my expected result will be 0.12% only
Using (\d.*) captures the first encounter of a digit followed by the rest of the line.
To match the digit with an optional decimal part followed by a percentage sign at the end of the string:
\b\d+(?:\.\d+)?%$
Explanation
\b A word boundary to prevent a partial word match\d+(?:\.\d+)? Match 1+ digits with an optional decimal part% Match literally$ End of string