I am having the three output results as below,
structure(c("[1] \"lls_loess\" \"lls_rlr\" \"knn_loess\"",
"[1] \"lls_loess\" \"lls_rlr\" \"knn_loess\"", "[1] \"lls_loess\" \"lls_rlr\" \"lls_vsn\" "
), dim = c(1L, 3L), dimnames = list(NULL, c("Based_on_PCV", "Based_on_PEV",
"Based_on_PMAD")))
I have used the names()
code for extracting the names from the result output.
And I want to give the output to the user in the format as in the picture.
Please suggest some R code for this matter.
Well... this is some quite ugly data, one possible solution
x=structure(c("[1] \"lls_loess\" \"lls_rlr\" \"knn_loess\"",
"[1] \"lls_loess\" \"lls_rlr\" \"knn_loess\"", "[1] \"lls_loess\" \"lls_rlr\" \"lls_vsn\" "
), dim = c(1L, 3L), dimnames = list(NULL, c("Based_on_PCV", "Based_on_PEV",
"Based_on_PMAD")))
df=data.frame(x)
data.frame(
sapply(
sapply(
df,
function(i){
strsplit(
gsub('"',",",gsub('\\[[0-9]+\\]| ',"",i)),
","
)
}
),
function(j){j[j!=""]}
)
)
Based_on_PCV Based_on_PEV Based_on_PMAD
1 lls_loess lls_loess lls_loess
2 lls_rlr lls_rlr lls_rlr
3 knn_loess knn_loess lls_vsn