finding divisor with condition with python using 'if' and 'while'

Question

trying to find how many divisors in 120, and printing divisors

div_n = 1
count = 0
n = 120

while div_n <= n:
    if n % div_n == 0:
        print(div_n)
        count += 1
    div_n += 1
print('number of divisor that 120 is {}.'.format(count))

the output should be

1
2
3
4
5
6
8
10
12
15
20
24
30
40
60
120
number of divisor that 120 is 16

But the problem I'm trying to solve says the code is not meeting the requirements. If there is nothing wrong, or more information is needed let me know.

Answer 1

You can use this:

def get_factors(n):
    ret = []
    for i in range(1, n+1):
        if not n % i:
            ret.append(i)
    return ret

factors = get_factors(120)
print(*factors, sep='\n')
print('Total factors:', len(factors))

Output:

1
2
3
4
5
6
8
10
12
15
20
24
30
40
60
120
Total factors: 16