here is the code snippet that I trying to launch url,
onPressed: () async {
final Uri url = Uri.parse(state.web);
if ( await canLaunchUrl(url)) {
aunchUrl(url);
}else{
printLogs('cannot launch');
}
},
state.web is https://www.facebook.com/xxxxxxx/
- this is comes from API,
and also I've tried below method as well,
onTap: () async {
final Uri url = Uri(scheme: 'https', host: state.web, path:'');
if (!await launchUrl(url,
mode: LaunchMode.externalApplication)) {
throw 'Could not launch $url';
}
},
second method is working if there is only www.facebook.com, I need to add /xxxxxxx/ complete url. Is there any method to separate this /xxxxxxx/ part and get it separately ?
problem is above both methods are not working. requirement is open the url in browser/related application.
firstly, split the url string, after split it can get the url like an array, like below,
[0]: "www.facebook.com"
[1]: "xxxxxxx"
then we can use the below method to launch the url in browser.
onPressed: () async {
final String source = https://www.facebook.com/xxxxxxx/;
final splitedString = source.split('/');
final Uri url = Uri(
scheme: 'https',
host: splitedString[0],
path: '/${splitedString[1]}/');
if (!await launchUrl(url,
mode: LaunchMode.externalApplication)) {
throw 'Could not launch $url';
}
},