Is there a method to get all groups in regular expression with wildcard in python

Question

Just like the follow code, there is not all groups. Is there a method to get all groups? Thanks~

import re

res = re.match(r'(?: ([a-z]+) ([0-9]+))*', ' a 1 b 2 c 3')

# echo ('c', '3'), but I want ('a', '1', 'b', '2', 'c', '3')
res.groups()

Answer 1

You could use re.finditer to iterate the matches, appending each result to an empty tuple:

import re

res = tuple()
matches = re.finditer(r' ([a-z]+) ([0-9]+)', ' a 1 b 2 c 3')
for m in matches:
    res = res + m.groups()

Output:

('a', '1', 'b', '2', 'c', '3')

Note that in the regex the outer group is removed as it is not required with finditer.