Extract numbers from an Array which has more than one string element

Question

An array has 4 elements. I want only the the thousands to printed out.

my_array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
            'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']

Expected output is:

[‘5000’, ‘5000’, ‘15000’, ‘10000’]

Answer 1

Use re.search, which extract the first match to the pattern of 1 or more digit, followed by 3 zeros.

import re

my_array = ['STK72184 4/28/2022 50 from Exchange Balance, 50 from Earning Balance & 10 from Bonus 5000 Regular 10/20/2023 Approved 4/28/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 5000 Regular 10/19/2023 Approved 4/27/2022',
            'STK725721 4/27/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 15000 Regular 10/19/2023 Approved 4/27/2022',
            'STK722222 4/26/2022 50 from Exchange Balance, 40 from Earning Balance & 10 from Bonus Balance 10000 Regular 10/18/2023 Approved 4/26/2022']

# If you want strings:
nums = [re.search(r'\d+000', s)[0] for s in my_array]
print(nums)
# ['5000', '5000', '15000', '10000']

# If you want integers:
nums = [int(re.search(r'\d+000', s)[0]) for s in my_array]
print(nums)
# [5000, 5000, 15000, 10000]