I'm new in batch scripting and a lot of things are still not 100% understandable for me.
I've found some sources (Source1, Source2) about substrings but I still can't figure how to replace characters before a delimiter.
I have files called like this :
File 1 : rem1020aa_10.zip
File 2 : com12909aa_32.zip
File 3 : fig129439aa_324.zip
As you can see my strings can have different lengths. All I want to do is replace the "aa" with something else.
Update - Sorry forgot to mention that I want to replace before the _ delimiter.
For exemple : rem1020duh_10.zip
Watch my current code :
@echo off
setlocal enableDelayedExpansion
set arg1=%1
for /f "delims=" %%b in ('dir /b /s /a-d "C:\Test"') do (
set "arg1=%%~nxc"
echo !arg1:~-6,2!
)
The result I get :
09
43
0a
I know that it will not work in that case because the lengths are different, but it's one method between multiple I tried.
I tried the first answer from Source2 too but still I can't find a way to do that.
@ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
SET "sourcedir=u:\your files"
SET "replaceme=aa"
SET "replacement=duh"
FOR /f "delims=" %%b IN ('dir /b /a-d "%sourcedir%\*" ') DO (
ECHO found filename "%%b"
rem store name part before "_" in `fileprefix
FOR /f "tokens=1*delims=_" %%q IN ("%%~nb") DO (
ECHO q=%%q r=%%r
SET "fileprefix=%%q"
rem is the 2-character string at the end of fileprefix "aa"? - note: /i means case-insensitive
IF /i "!fileprefix:~-2!"=="%replaceme%" (
ECHO %%q ends %replaceme%
ECHO so new name is !fileprefix!, except the last 2 characters + replacement + _ + %%r
ECHO and extension is %%~xb
ECHO REN "%%b" "!fileprefix:~0,-2!%replacement%_%%r%%~xb"
)
)
ECHO ----------------------
)
GOTO :EOF
This should demonstrate how I might approach this problem. The steps are echoed - obviously, those echoes could be deleted once the method is understood.
Note that it would also be possible to use "%sourcedir%\*%replaceme%_*" as the filemask which would reduce the incidence of filenames detected that do not fit the criteria required.