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bashconditional-statementslogicbash-completion

bash code to count A to z char with count string input string and give output in new string

Hi folks just started write code in bash but stuck in my own question in want to count a to alphabets repetation in string like

read -p 'enter the string' str # SUPPOSE STRING USER ENTER IS

input = AAASSSSFFRREEE

i wanna get output like= A3S4F2R2E3

what can i do i am trying with for condition and this program is making monkey out of me

Solution

    • grep -o, --only-matching

      Print only the matched (non-empty) parts of a matching line, with each such part on a separate output line. Using . as pattern for every character

    grep -o . <<<"AASS"
A
A
S
S

    • uniq -c, --count

      prefix lines by the number of occurrences

    grep -o . <<<"AASS"|uniq -c
      2 A
      2 S

    • awk '{printf "%s%d", $2,$1}'

      Reorder the output. Character '$2' first then number '$1'. Print all in a single line

    grep -o . <<<"AASS"|uniq -c|awk '{printf "%s%d", $2,$1}END{print ""}'
A2S2

    Unsorted alphabet

    $ string="AAASSSSFFRREEE" 
$ grep -o . <<<"$string"|uniq -c|awk '{printf "%s%d", $2,$1}END{print ""}'
A3S4F2R2E3
$ string="AAASSSSFFRREEEAAAAFFFFFEE"
A3S4F2R2E3A4F5E2

    Sorted alphabet

    $ string="AAASSSSFFRREEE" 
$ grep -o . <<<"$string"|sort|uniq -c|awk '{printf "%s%d", $2,$1}END{print ""}'
A3E3F2R2S4
$ string="AAASSSSFFRREEEAAAAFFFFFEE"
A7E5F7R2S4