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pythonparsingurl

How to get everything after last slash in a URL?

How can I extract whatever follows the last slash in a URL in Python? For example, these URLs should return the following:

URL: http://www.test.com/TEST1
returns: TEST1

URL: http://www.test.com/page/TEST2
returns: TEST2

URL: http://www.test.com/page/page/12345
returns: 12345

I've tried urlparse, but that gives me the full path filename, such as page/page/12345.

Solution

  • You don't need fancy things, just see the string methods in the standard library and you can easily split your url between 'filename' part and the rest:

    url.rsplit('/', 1)

    So you can get the part you're interested in simply with:

    url.rsplit('/', 1)[-1]