I extracted a file that comes in a zip and looks similar to this:
Payload =
<?xml version="1.0" encoding="UTF-8"?>
<worksheet xmlns="http://schemas.openxmlformats.org/spreadsheetml/2006/main"><dimension ref="A1"/><sheetViews><sheetView workbookViewId="0" tabSelected="true"/></sheetViews><sheetFormatPr defaultRowHeight="15.0"/><sheetData>
<row r="1">
<c r="A1" t="inlineStr"><is><t>First</t></is></c><c r="B1" t="inlineStr"><is><t>Middle</t></is></c><c r="C1" t="inlineStr"><is><t>Last</t></is></c><c r="D1" t="inlineStr"><is><t>SSN</t></is></c><c r="E1" t="inlineStr"><is><t>Street</t></is></c><c r="F1" t="inlineStr"><is><t>MailingState</t></is></c><c r="G1" t="inlineStr"><is><t>Code</t></is></c><c r="H1" t="inlineStr"><is><t>MailingCountry</t></is></c><c r="I1" t="inlineStr"><is><t>Birthdate</t></is></c><c r="J1" t="inlineStr"><is><t>name</t></is></c><c r="K1"
<row r="2">
<c r="A2" t="inlineStr"><is><t>William</t></is></c><c r="A5" t="inlineStr"><is><t></t></is></c><c r="B2" t="inlineStr"><is><t>William</t></is></c><c r="D2" t="inlineStr"><is><t>123456798</t></is></c><c r="E2" t="inlineStr"><is><t>Test</t></is></c><c r="F2" t="inlineStr"><is><t>XX</t></is></c><c r="G2" t="inlineStr"><is><t>12345</t></is></c><c r="H2" t="inlineStr"><is><t></t></is></c><c r="I2" t="inlineStr"><is><t>1992-13-11T04:00:00</t></is></c><c r="J2"
mediaType = application/java; charset=UTF-8
How can I convert that file to something that I can manipulate better, for example JSON.
Mule Runtime version 4.4.0 EE
Use the read() function to parse it as the XML file the content appears to be, then transform to whatever you want.
Example DataWeave transformation:
output application/json
---
read(payload, "application/xml")
Note that the payload seems truncated. If it is really XML above script will work. Also I recommend to perform any transformation before outputting to JSON, to avoid performance issues. If you are doing more transformations later in the flow is better to output to application/java and convert to JSON in the last transformation.