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How to search for 2 single quote signs ('') in a LIKE statement?

I have a text field which I need to check if this char combination '' (not to be confused with ") appears anywhere in the column.

This SQL code

SELECT TEXTFIELD
FROM MYTABLE
WHERE TEXTFIELD LIKE '%''%'

returns text like

BARN'S

which does not contain 2 single quote signs next to each other.

How can I filter correctly?

Solution

  • You need to escape the quotes i.e.

    SELECT TEXTFIELD
FROM MYTABLE
WHERE TEXTFIELD LIKE '%''''%'