How to make if inside for loop using lambda?

Question

I have list_a and string_tmp like this

list_a = ['AA', 'BB', 'CC']
string_tmp = 'Hi AA How Are You'

I want to find out is there any of string_tmp items in the list_a, if it is, type = L1 else type = L2?

# for example
type = ''
for k in string_tmp.split():
    if k in list_a:
        type = 'L1'
if len(type) == 0:
    type = 'L2'

this is the real problem but in my project, len(list_a) = 200,000 and len(strgin_tmp) = 10,000, so I need that to be super fast

# this is the output of the example 
type = 'L1'

Answer 1

Converting the reference list and string tokens to sets should enhance performance. Something like this:

list_a = ['AA', 'BB', 'CC']
string_tmp = 'Hi AA How Are You'

def get_type(s, r): # s is the string, r is the reference list
    s = set(s.split())
    r = set(r)
    return 'L1' if any(map(lambda x: x in r, s)) else 'L2'

print(get_type(string_tmp, list_a))

Output:

L1