How to get the seven segment output side by side in python?

Question

I have written a code to display the seven segment output. Whereas I need to display the output side by side. Say input: 123 , output should display seven segment side by side as below

#  ### ###   
#    #   #
#  ### ###
#  #     #
#  ### ###

Here is my logic:

dict = {0:('###','# #','# #','# #','###'),
        1:('  #','  #','  #','  #','  #'),
        2:('###','  #','###','#  ','###'),
        3:('###','  #','###','  #','###'),
        4:('#  ','#  ','###','  #','  #'),
        5:('###','#  ','###','  #','###'),
        6:('###','#  ','###','#  ','###'),
        7:('###','  #','  #','  #','  #'),
        8:('###','# #','###','# #','###')}
value = input("enter value:")
for i in value:
    list1 = dict.get(int(i))
    print('\n'.join(list1))

Answer 1

Try the following:

dict = {0:('###','# #','# #','# #','###'),
        1:('  #','  #','  #','  #','  #'),
        2:('###','  #','###','#  ','###'),
        3:('###','  #','###','  #','###'),
        4:('#  ','#  ','###','  #','  #'),
        5:('###','#  ','###','  #','###'),
        6:('###','#  ','###','#  ','###'),
        7:('###','  #','  #','  #','  #'),
        8:('###','# #','###','# #','###')}
value = input("enter value:")
for seg in range(5):
    print(' '.join([dict.get(int(i))[seg] for i in value]))

You need to print the segments side by side, so you should start by printing the top column of all the numbers, the second, and so on. I'm using a list comprehension to join the numbers together for each column.