I am reading file using LazyCsvReader and the file contains a date column. LazyCsvReader read the date as string. The date is in format "%m-%d-%Y". How to properly handle it as date. There is a page for this but it is for python. I tried to read the documentation but couldn't figure it out. Following is my try case which doesn't compile
use polars::prelude::*;
use polars_lazy::prelude::*;
use chrono::prelude::*;
use polars_core::time::*;
fn main() {
let lf = read_csv_lazy("file.csv").unwrap();
let out = lf.clone()
.with_column((col("InvoiceDate").utf8().strptime("%m-%d-%Y")))
.collect();
println!("{:?}", out3);
}
fn read_csv_lazy(file_name: &str) -> Result<LazyFrame> {
let lf: LazyFrame = LazyCsvReader::new(file_name.into())
.has_header(true)
.with_encoding(CsvEncoding::LossyUtf8)
.finish()?;
Ok(lf)
}
I am getting following error
error[E0599]: no method named `utf8` found for enum `Expr` in the current scope
--> src/main.rs:20:38
|
20 | .with_column((col("InvoiceDate").utf8().strptime("%m-%d-%Y")))
| ^^^^ method not found in `Expr`
Polars Expressions
cannot be downcasted unless you map
or apply
a closure over the underlying Series
.
However, in this case you don't need any closure. You can use the str
namespace, available under the Expr::str()
method.
let options = StrpTimeOptions {
fmt: Some("%m-%d-%Y".into()),
..Default::default()
};
let my_expr = col("InvoiceDate").str().strptime(options);