Separate lines with keys and store in different files

Question

How to separate (get) the entire line related to hexadecimal number keys and the entire line for DEBUG in a text file, then store in different file, where the key is in this format: "[ uid key]"? i.e. ignore any lines that is not DEBUG.

in.txt:

  [ uid 28fd4583833] DEBUG web.Action
  [ uid 39fd5697944] DEBUG test.Action
  [ uid 56866969445] DEBUG test2.Action
  [ uid 76696944556] INFO  test4.Action
  [ uid 39fd5697944] DEBUG test7.Action
  [ uid 85483e10256] DEBUG testing.Action

The output files are named as "out" + i + ".txt", where i = 1, 2, 3, 4. i.e.

out1.txt:

  [ uid 28fd4583833] DEBUG web.Action

out2.txt:

  [ uid 39fd5697944] DEBUG test.Action
  [ uid 39fd5697944] DEBUG test7.Action

out3.txt:

  [ uid 56866969445] DEBUG test2.Action

out4.txt:

  [ uid 85483e10256] DEBUG testing.Action

I tried:

awk 'match($0, /uid ([^]]+)/, a) && /DEBUG/ {print > (a[1] ".txt")}' in.txt

Answer 1

If your file format is consistent as you show, you can just do:

awk '
    $4!="DEBUG" { next }
    !($3 in f) { f[$3] = "out" (++i) ".txt" }
    { print > f[$3] }
' in.txt

---

Or to avoid the open file issue mentioned in the comment:

awk '
    $4!="DEBUG" { next }
    !($3 in f) { f[$3] = "out" (++i) ".txt" }
    {
        o = f[$3]
        if (o!=p && p) close(p)
        print >> o
        p = o
    }
' in.txt