pythontkinterkeyboard-eventstkinter-entry
Using backspace across multiple tkinter Entry widgets
I made wordle (using tkinter) in a previous project of mine, and now instead of using one entry to get the guess, I want 5 entries linked together that work like the blocks in:
In the image, you can backspace across these "linked" entries. I got the typing across entries figured out, but how do I delete across them?
from tkinter import *
root = Tk()
root.geometry('400x400')
def testlen():
global textinentry1, textinentry2, textinentry3, textinentry4, textinentry5
textinentry1= entry1.get()
textinentry2= entry2.get()
textinentry3= entry3.get()
textinentry4= entry4.get()
textinentry5= entry5.get()
if len(textinentry1) >1 :
entry1.delete(0,END)
entry1.insert(0,textinentry1[0])
entry2.delete(0, END)
entry2.insert(0,textinentry1[1] )
entry2.focus_set()
if len(textinentry2) >1 :
entry2.delete(0,END)
entry2.insert(0,textinentry2[0])
entry3.delete(0, END)
entry3.insert(0,textinentry2[1] )
entry3.focus_set()
if len(textinentry3) >1 :
entry3.delete(0,END)
entry3.insert(0,textinentry3[0])
entry4.delete(0, END)
entry4.insert(0,textinentry3[1] )
entry4.focus_set()
if len(textinentry4) >1 :
entry4.delete(0,END)
entry4.insert(0,textinentry4[0])
entry5.delete(0, END)
entry5.insert(0,textinentry4[1] )
entry5.focus_set()
if len(textinentry5) > 1:
entry5.delete(0,END)
entry5.insert(0,textinentry5[0])
entry1 = Entry(root,width=3, font = ('Georgia 18'), justify=CENTER)
entry1.grid(row=0, column=0)
entry2 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry2.grid(row=0, column=1)
entry3 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry3.grid(row=0, column=2)
entry4 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry4.grid(row=0, column=3)
entry5 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry5.grid(row=0, column=4)
def loop():
testlen()
root.after(1,loop) # 1 is 1 millisecond. Here root.after method calls the loop
# function after 1 millisecond without crashing your code.
loop()
root.mainloop()
Solution
First, you have to get something to register a button press. For this, I imported keyboard and used if keyboard.is_pressed("backspace"): to see if backspace was pressed.
Unfortunately, when a human presses a button, we hold it down for a few milliseconds so to the computer, we press it more then once. To prevent this, I imported time and found that using time.sleep(.15)was the best delay because it stopped me from accidentally pressing it more then once, and I could also hold it down without the code slowly erasing each character.
This could be better condensed with a loop but my code for the standalone boxes is:
from tkinter import *
import keyboard, time
root = Tk()
root.geometry('400x400')
def testlen():
global textinentry1, textinentry2, textinentry3, textinentry4, textinentry5, whathasfocus
whathasfocus= root.focus_get()
textinentry1= entry1.get()
textinentry2= entry2.get()
textinentry3= entry3.get()
textinentry4= entry4.get()
textinentry5= entry5.get()
if whathasfocus == entry1:
if len(textinentry1) >= 1:
pass
elif len(textinentry1) == 0:
if keyboard.is_pressed("delete"):
time.sleep(.15)
entry1.delete(0,END)
entry1.focus_set()
if whathasfocus == entry2:
if len(textinentry2) >= 1:
pass
elif len(textinentry2) == 0:
if keyboard.is_pressed("backspace"):
time.sleep(.15)
entry2.delete(0,END)
entry1.focus_set()
if keyboard.is_pressed("delete"):
time.sleep(.15)
entry2.delete(0,END)
entry2.focus_set()
if whathasfocus == entry3:
if len(textinentry3) >= 1:
pass
elif len(textinentry3) == 0 :
if keyboard.is_pressed("backspace"):
time.sleep(.15)
entry3.delete(0,END)
entry2.focus_set()
if keyboard.is_pressed("delete"):
time.sleep(.15)
entry3.delete(0,END)
entry3.focus_set()
if whathasfocus == entry4:
if len(textinentry4) >= 1:
pass
elif len(textinentry4) == 0:
if keyboard.is_pressed("backspace"):
time.sleep(.15)
entry4.delete(0,END)
entry3.focus_set()
if keyboard.is_pressed("delete"):
time.sleep(.15)
entry4.delete(0,END)
entry4.focus_set()
if whathasfocus == entry5:
if len(textinentry5) >= 1:
pass
elif len(textinentry5) == 0:
if keyboard.is_pressed("backspace"):
time.sleep(.15)
entry5.delete(0,END)
entry4.focus_set()
if len(textinentry1) >1 :
entry1.delete(0,END)
entry1.insert(0,textinentry1[0])
entry2.delete(0, END)
entry2.insert(0,textinentry1[1] )
entry2.focus_set()
if len(textinentry2) >1 :
entry2.delete(0,END)
entry2.insert(0,textinentry2[0])
entry3.delete(0, END)
entry3.insert(0,textinentry2[1] )
entry3.focus_set()
if len(textinentry3) >1 :
entry3.delete(0,END)
entry3.insert(0,textinentry3[0])
entry4.delete(0, END)
entry4.insert(0,textinentry3[1] )
entry4.focus_set()
if len(textinentry4) >1 :
entry4.delete(0,END)
entry4.insert(0,textinentry4[0])
entry5.delete(0, END)
entry5.insert(0,textinentry4[1] )
entry5.focus_set()
if len(textinentry5) > 1:
entry5.delete(0,END)
entry5.insert(0,textinentry5[0])
entry1 = Entry(root,width=3, font = ('Georgia 18'), justify=CENTER)
entry1.grid(row=0, column=0)
entry1.focus_set()
entry2 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry2.grid(row=0, column=1)
entry3 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry3.grid(row=0, column=2)
entry4 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry4.grid(row=0, column=3)
entry5 = Entry(root, width=3, font = ('Georgia 18'), justify=CENTER)
entry5.grid(row=0, column=4)
def loop():
testlen()
root.after(1,loop) # 1 is 1 millisecond. Here root.after method call the loop function after 1 millisecond without crashing your code.
loop()
root.mainloop()