Im trying to start this script with a argument.
When i start the script from a terminal i want to type "python test.py C:\Users\etc\etc\log.log count" to run func1 or error to run func3.
I have try to play around with sys.argv / sys.argv[2] but i cant get it to work.
import sys
def func1():
count = 0
with open(r'C:\Users\etc\etc\log.log') as logfile:
lines = logfile.readlines()
for error in lines:
count += error.count('[error]')
print('errors', count)
def func3():
import re
with open(r'C:\Users\etc\etc\log.log') as logfile:
for line in map(str.strip, logfile):
m = re.findall('\[.*?\]', line)
if len(m) > 1 and m[1] in ('[error]'):
offset = line.find(m[1]) + len(m[1]) + 1
print(m[0], line[offset:])
if __name__ == '__main__':
func1()
func3()
sys.argv is a list containing the arguments passed to the program. The first item is the file name, the rest are the arguments so to get the first argument you use sys.argv[1].
Because the first argument isn't necessarily provided, I've used a try/except block to catch the possible IndexError. You can handle this however you like.
You can then just use an if statement to decide which function to run.
import sys
def func1():
count = 0
with open(r'C:\Users\etc\etc\log.log') as logfile:
lines = logfile.readlines()
for error in lines:
count += error.count('[error]')
print('errors', count)
def func3():
import re
with open(r'C:\Users\etc\etc\log.log') as logfile:
for line in map(str.strip, logfile):
m = re.findall('\[.*?\]', line)
if len(m) > 1 and m[1] in ('[error]'):
offset = line.find(m[1]) + len(m[1]) + 1
print(m[0], line[offset:])
if __name__ == '__main__':
try:
arg = sys.argv[1]
except: pass
else:
if arg == "count":
func1()
elif arg == "error":
func3()