I have this string
cmd = "show run IP(k1) new Y(y1) add IP(dev.maintserial):Y(dev.maintkeys)"
What is a regex to first match exactly "IP(dev.maintserial):Y(dev.maintkeys)"
There might be a different path inside the parenthesis, like (name.dev.serial), so it is not like there will always be one dot there.
I though of something like this:
re.search('(IP\(.*?\):Y\(.*?\))', cmd) but this will also match the single IP(k1) and Y(y1
My usage will be:
If "IP(*):Y(*)" in cmd:
do substitution of IP(dev.maintserial):Y(dev.maintkeys) to Y(dev.maintkeys.IP(dev.maintserial))
How can I then do the above substitution? In the if condition I want to do this change in order: from IP(path_to_IP_key):Y(path_to_Y_key) to Y(path_to_Y_key.IP(path_to_IP_key)) , so IP is inside Y at the end after the dot.
Something like this?
r"IP\(([^)]*\..+)\):Y\(([^)]*\..+)\)"
You can try it with your string. It matches the entire string IP(dev.maintserial):Y(dev.maintkeys) with groups dev.maintserial and dev.maintkeys.
The RE matches IP(, zero or more characters that are not a closing parenthesis ([^)]*), a period . (\.), one or more of any characters (.+), then ):Y(, ... (between the parentheses -- same as above), ).
Example Usage
import re
cmd = "show run IP(k1) new Y(y1) add IP(dev.maintserial):Y(dev.maintkeys)"
# compile regular expression
p = re.compile(r"IP\(([^)]*\..+)\):Y\(([^)]*\..+)\)")
s = p.search(cmd)
# if there is a match, s is not None
if s:
print(f"{s[0]}\n{s[1]}\n{s[2]}")
a = "Y(" + s[2] + ".IP(" + s[1] + "))"
print(f"\n{a}")
Above p.search(cmd) "[s]can[s] through [cmd] looking for the first location where this regular expression [p] produces a match, and return[s] a corresponding match object" (docs). None is the return value if there is no match. If there is a match, s[0] gives the entire match, s[1] gives the first parenthesized subgroup, and s[2] gives the second parenthesized subgroup (docs).
Output
IP(dev.maintserial):Y(dev.maintkeys)
dev.maintserial
dev.maintkeys
Y(dev.maintkeys.IP(dev.maintserial))