Does ruamel.yaml have a function to do the process with all files in one directory?
Something like this:
data = yaml.load(Path("*.*"))
No, it does not, but you can do it one line (assuming you have the imports and the YAML()
instance):
from pathlib import Path
import ruamel.yaml
yaml = ruamel.yaml.YAML()
data = [yaml.load(p) for p in Path('.').glob('*.yaml')]