Ruby, How I can obtain the whole namespace definition path for a method inside the same method?

Question

How I can obtain the whole namespace definition path for a method inside the same method?

Using this example to make easy the question:

module Parent
    module Child
        def self.get_complete_namespace
            this_path = ???
            puts this_path.to_s
        end
    end
end

Parent::Child.get_complete_namespace
#=> "Parent::Child.get_complete_namespace"

So to puts or print out this string "Parent::Child.get_complete_namespace", what is the "this_path" variable value using self super o something like that?

Answer 1

I don't know of any existing functions for this, though you could pretty easily create one using __callee__ (or __method__)

module Parent
  module Child
    def self.get_complete_namespace
      m = method(__callee__)
      "#{m.receiver.name}.#{m.name}"
    end
  end
end

Parent::Child.get_complete_namespace
#=> "Parent::Child.get_complete_namespace"

Some usages notes:

• __callee__ and __method__ will usually return the same symbol. If the method is aliased, then __callee__ returns the method name that was invoked, while __method__ will return the method name as it was defined.
• For a class/module method, you need to use m.receiver. For an instance method, you need to use m.owner. See Method.

Class example:

module Parent
  class Child
    def self.get_complete_namespace
      m = method(__callee__)
      "#{m.receiver.name}.#{m.name}"
    end

    def get_complete_namespace
      m = method(__callee__)
      "#{m.owner.name}.#{m.name}"
    end

    alias_method :complete, :get_complete_namespace
  end
end

Parent::Child.get_complete_namespace
#=> "Parent::Child.get_complete_namespace"

Parent::Child.new.get_complete_namespace
#=> "Parent::Child.get_complete_namespace"

Parent::Child.new.complete
#=> "Parent::Child.complete"

Edit - one-liner version:

def self.get_complete_namespace
  method(__callee__).instance_eval { "#{receiver.name}.#{name}" }
end